GAGING PROMOTED. AN APPENDIX TO Stereometrical Propositions.

By ROBERT ANDERSON.

LONDON, Printed by I. W. for Ioshua Coniers, at the Raven in Ducklane, 1669.

Gaging Promoted AN APPENDIX TO Stereometrical Propositions.

I. Note.

AS an Abstract from the undoubted Axioms of Geometry, it is generally observed, that in a Rank of numbers, having equal diffe­rence, the second differences of the squares of those numbers are equal; the third differences of the cubes of those numbers are equal: and so in order in the higher powers. Thus, [Page 2]

In Squares1
1 1    
3
2 4 2
5
3 9 2
7
4 16 2
9
5 25  
 
1 2 3 4

2
1 1    
8
3 9 8
16
5 25 8
24
7 47 8
32
9 81  
 
1 2 3 4

Observe in the first of these Examples, in the first collum are the numbers of a progressition, having equal difference, to wit, a unite. In the second co­lum, the squares of those numbers. In the third co­lum, the first differences. In the fourth colum, the second differences, to wit, 2, 2, 2. In the second Example, in the first colum are a Rank of numbers, having equal difference, to wit, 2. In the second colum, their squares. In the third colum, the first difference. In the fourth colum, the second diffe­rence.

II. Note.

Hence it follows, that by the help of such diffe­rences the table of squares may be calculated: thus, in the first Example, the sum of 1 and 3, is 4; the square of 2. The sum of 2, 3 and 4, is 9; the square of 3. The sum of 2, 5 and 9, is 16; the square of 4. The sum of 2, 7 and 16, is 25; the square of 5. The sum of 2, 11 and 36, is 49; the square of 7. &c.

III. Note.

Like plain numbers are in the same proportion one to another, that a square number is in, to a square number: Euclide the 26 Proposition of the Eighth Book. Therefore the second difference in such a Rank of plane numbers are equal. Further, what planes and solids are either equal or propor­tionable to such Ranks may be gradually calculated; as in the last.

IV. Note.

1 1      
7
2 8 12  
19 6
3 27 18
37 6
4 64 24
71  
5 125  
   
1 2 3 4 5

1 1      
26
3 27 72
98 48
5 125 120
218 48
7 343 186
386  
9 729  
 
1 2 3 4 5

In the first Example, in the first colum are the numbers in a Rank having equal difference, to wit, a unite. In the second colum, the cubes of those numbers. In the third colum, the first differences of those cubes. In the fourth colum, the second differences. In the fifth colum, the third differen­ces, to wit, 6, 6. The like in the second Example.

V. Note.

Hence it follows, that the table of cubes may be [Page 4] made thus: In the first Example, 1 and 7, is 8; the cube of 2. The sum of 8 and 19, is 27; the cube of 3. The sum of 18, 19 and 27, is 64; the cube of 4. The sum of 6, 18, 37 and 64, is 125; the cube of 5. The sum of 6, 24, 61 and 125, is 216; the cube of 6. The sum of 6, 30, 91 and 216, is 343; the cube of 7. The like in the second Example.

VI. Note.

Like solid numbers are in the same proportion one to another, that a cube number is in, to a cube number▪ Euclide the XXVII Prop. of the Eighth Book. Therefore the third differences in such a Rank of solid numbers are equal: further, such planes and solids as are either equal or proportio­nable to such Ranks, may be gradually calculated, as in the last.

VII. Note.

If a Rank of Squares, whose Roots have equal differences, be multiplied by any number, the se­cond differences of such a Rank of proucts are e­qual. Let the number multiplying be 10.

0 0 00    
10
1 1 10 20
30
2 4 40 20
50
3 9 90 10
70
4 16 160 20
90
5 25 250  
 
1 2 3 4 5

In the first colum are the num­bers bearing equal difference. In the second colum are the squares of those numbers. In the third colum the products. In the fourth colum the first differences. In the fifth colum the second differences and they equal.

VIII. Note.

If unto such a Rank of Products, as in the last, there be added a Rank of Cubes, whose Roots are equal to the Roots of the Squares, the third diffe­rences of such a Rank will be equal.

0 00 0 00      
11
1 10 1 11 26  
37 6
2 40 8 48 32
69 6
3 90 27 117 38
107 6
4 160 64 224 44
151  
5 250 125 375  
   
1 2 3 4 5 6 7

In the first colum are the numbers having equal difference. In the second colum the Products of their squares by a given number. In the third co­lum the cube of the numbers in the first colum. In the fourth colum the sum of the products and cubes. In the fifth colum their first difference. In the sixt colum the second differences. In the seventh co­lum the third differences which are equal.

IX. Note.

Let a constant number be added to a Rank of Products, so that one of the numbers multiplying [Page 6] be a constant number, and the other of the num­bers be the squares of numbers having equal diffe­rence, and this Rank of sums be added to a Rank of cubes, whose roots are the same with the roots of the squares; such a compounded Rank will have their third difference equal. Thus,

1 8 10 1 19      
37
2 8 40 8 56 32  
69 6
3 8 90 27 125 38
107 6
4 8 160 64 232 44
151  
5 8 250 125 383  
   
1 2 3 4 5 6 7 8

In the first colum are the numbers having equal difference. In the second colum is constant number to be added. In the third colum are the Rank of products, that is, the squares of the num­bers in the first colum multiplied by a given num­ber. In the fourth colum are the cubes of the num­bers in the first colum. In the fifth colum are the sum of the numbers in the second, third and fourth colums. In the sixth colum are the first differences of their sums. In the seventh colum are the second differences. In the eighth colum the third differen­ces, and they equal.

X. Note.

In a Rank of numbers, having equal difference, and equal in number; if the third part of the cubes of each of these numbers, be substracted from the products of the squares of each of these numbers, in half the greatest number of that Rank, the re­mainders [Page 7] will be a Rank of numbers, equal to all the squares in the several portions of one fourth of a sphere, whose diameter is equal to the greatest number in that Rank, and the third differences of this Rank of portions are equal; but the first and second differences will increase and decrease, diffe­rently one from another. Thus,

0 00 00 00      
99
3 09 108 99 162  
261 54
6 72 432 360 108
369 54
9 243 972 729 54
423 54
12 756 1728 1152 00
423 54
15 1125 2700 1575 54
369 54
18 1944 3888 1944 108
261 54
21 3087 5292 2205 162
96  
24 4608 6912 2304  
   
1 2 3 4 5 6 7

In the first colum are the numbers having equal difference. In the second colum are the pyramides adscribed within the cubes of the numbers in the first colum. In the third colum are the products of the squares of the numbers in the first colum, by half the greatest number in the first colum. In the fourth colum are the differences of the numbers in the second and third colums, that is, all the squares in several portions of one fourth of a sphere, whose diameter is 24. In the fifth colum are the first dif­ferences. In the sixt colum are their second diffe­rences. In the seventh colum are the third differen­ces, and they equal.

XI. Note. The Application or Vse of the Preceeding Notes.

The application or Use may be, to calculate Py­ramides and cones, either the whole or their parts▪ as also to calculate the parabolick and hyperbolick conoides, either the whole, or their frustums; yet also, to calculate the sphere or spheroide, either the whole or their portions or Zones, and that gradually, that is, to find the solidity upon every inch or foot.

To find the solidity of a parabolick Conoide upon every two inches.

To do which, consider the Diagram of the 18 Prop. of my Stereometrical Prop. Let PA be 16; AR 12; therefore AV or PH will be 9; for it ought to be as PA, is to AR; so is AR, to AV. Let the axis AP be divided into eight equal parts; viz. 2, 4, 6, 8, 10, 12, 14, 16. Let there be planes drawn parallel to the base, through every one of these divisions, though in the Diagram there is not so many. From P to the first Q suppose to be 2, its square 4; the half thereof 2, which multiplied by 9 equal to PH, the Product will be 18; that is, the Prism QZGIHP; equal to all the squares in the portion of the conoid QOP. Let from P, to the second Q be 4, its square 16, the half is 8; which [Page 9] multiplied by 9, the Product is 72; equal to the Prism QZFIHP, equal to all the squares in the portion of the conoid QOP. Let from P to the third Q be 6, its square 36, the half of it is 18, which multiplied by 9, the product is 162; the Prism QZEIHP; equal to all the squares in the third portion of the conoid QOP.

Having obtained two portions, the rest may be obtained thus: having obtained the second diffe­rence, which is 36, we may proceed to find the rest by the Seventh Note; thus, add 36 to 54, and it makes 90: which added to 72, the sum is 162, equal to all the squares in that portion, and so in order; 36, 90 and 162; the sum is 288. 36, 126 and 288; the sum is 450. 36, 162 and 450, the sum is 648, &c.

0 00    
8
2 18 36
54
4 72 36
90
6 162 36
126
8 28 [...] 36
62
10 45 [...] 36
198
12 648 36
234
14 882 36
270
16 1152  
 
1 2 3 4

In the first colum are the parts of the altitude of the conoid. In the second colum are all the squares in several portions of one fourth of a conoid. In the third colum the first differences. In the fourth colum the second differen­ces. These portions in the second colum may be reduced to circular portions, thus, as 14 is to 11; so are all the squares in these porti­ons to the portions themselves.

I. Scholium:

The use of this gradual calculation may be thus: Suppose a Brewers Copper be in form of a para­bolick [Page 10] conoid; the quantity of liquor therein con­tained may be found, thus, having calculated a table upon every inch, or two inches, or as is thought convenient; then having a straight Ru­ler divided equally into inches, putting the Ruler into the liquor to the bottom of the Copper, see how many inches of the Ruler is wet; with the number of wet inches enter the first colum of your table, and in the next colum are the number of cu­bick inches which that portion contains; the num­ber of cubick inches thus found, being divided by the number of cubick inches in a Gallon, the quo­tient shews the number of Gallons in that portion of the Copper.

II. Scholium: To compose several works into one.

As 14, is to 11; so are all the squares in one fourth of the conoid, to one fourth of the conoid it self. because this one fourth ought to be di­vided by the number of cubick inches in a Gal­lon, suppose it 288, to shew the number of Gal­lons in each portion, we may multiply 14 by 288, that is 4032. Then as 4032 is to 11; so are all the squares in one fourth of the conoid, to the Gal­lons in that one fourth. Further, because this one fourth ought to be multiplied by 4, to reduce it to a whole conoid; therefore, divide the constant divisor, that is, 4032, by 4, and it will be 1008. Then, as 1008, is to 11; so are those several por­tions in the second colum of the last table, to the [Page 11] number of Gallons in those several portions of a parabolick conoid. By such compositions may the Practitioner compose constant divisors or divi­dends, which will much breviate the work; this is onely for an Example.

Every parabolick conoid hath its second diffe­rences equal. To find the second differences, work thus, Square one of the equal segments of the axis, and multiply that Square by the Parame­ter, that product will be the second difference. In this Example, the equal segment of the axis is 2, the square of it 4; which multiplied by the Para­meter 9, the product is 36, the second difference. Half of the second difference, is always the first of the first difference. Half 36 the second difference, is 18, the first of the first difference, &c. Here note, this 36 is the second difference of one fourth of all the squares in a parabolick conoid; if 36 be multiplied by 4, it makes the second difference 144; whose half is 72, the first of the first differences. Or, the first differences are found by taking half the difference of the squares of any two segments, which multiplied by the Parameter, thereby the first differences are obtained. Thus, to find the first difference answerable to the Segments 6 and 8; the Square of 8, is 64; the Square of 6, is 36; the difference of those Squares is 28, whose half is 14; which multiplied by the Parameter 9, the product is 126; the first difference answerable be­twixt 6 and 8.

XII. Note.To find the solidity of an hyperbolick conoid gra­dually, to wit, upon every three inches.

For the performance of which, take notice of the XVI Prop. of Stereom. Prop. in that Diagram, Let AM equal to AB be 9. Let ML equal to AF, be 6. Let AE be 15: therefore FE will be 9. Let the rest of the construction be as in that Pro­position. Let from M to the first K be 3, whose square is 9, whose half is 4½, the area KHM; which being multiplied by ML, 6; the product will be 27, the prism KHNOLM. Because FE, FC and FL are equal, that is, each of them 9: Therefore, the first pyramid ONXILM will be 9. Then this prism and pyramid being added, will make 36, the whole prism KHXILM, equal to all the squares in the portion KZM. Let from M to the second K be 6, whose square is 36, its half 18, the area KHM; which being multiplied by ML, 6; the product will be 108, equal to the prism KHNOLM. The cube of 6, is 216; a third part is 72, the pyramid ONXIL, this prism and pyramid be­ing added together, the sum will be 180; the prism KHXILM: equal to all the squares in the por­tion KZM. Let from M to A, be 9; its square 81, the half 40½, equal to the area ABM, which being multiplied by ML, 6; the product will be 243: the cube of 9, is 729; a third part thereof is 243; equal to the pyramid FCDEL: this prism and pyramid being added together, is 486; the [Page 13] whole prism ABDELM, equal to all the squares of the portion AZM.

These three portions being obtained, they may be continued by the VIII Note, thus:

0 00      
36  
3 46 108
144 54
6 180 162
306 54
9 486 216
522 54
12 1008 270
792 54
15 1800 324
1116 54
18 2216 378
1494 54
21 4410 432
1926  
24 6336  
   
1 2 3 4 5

For if the third dif­ferences which are e­qual, and in this Ex­ample is 54, be added to the first of the se­cond differences, be­ing 108, it makes 162, and by such additions, the second differences in the fourth colum are made. Further, by adding these second differences to the first of the first differences which is 36, it makes 144, &c. So the numbers in the third colum are made. Yet further, by adding these first differen­ces to the first number in the second colum, the Rank of portions of such a conoid is made.

Then,

By making use of the directions in the first and second Scholiums, the number of Gallons are ob­tained. The parabolick and hyperbolick conoides may well be made use of for Brewers Coppers; the parabolick, when the crown is somewhat blunt; but the hyperbolick conoid when the crown is more sharp.

XIII. Note. To calculate a Sphere gradually, to wit, upon every three Inches.

Consider the XV Prop. of Stereom. Prop. Let ED equal to EF, be 24. The rest of the constru­ction as in that Prop. Let from E, to the first R be 3, whose square is 9; whose half is 4½, the area RXE, which being multiplied by 24, the product will be 108; the prism KHXREF. The cube of 3, is 27; a third part thereof is 9, the pyramid KHOIF; this pyramid taken from the former prism, leaves the prism RXOIFE, 99: equal to all the squares in the portion RQE. From E, to the second R, 6; its square 36, the half 18, which multiplied by 24, makes 432; the prism RXHKFE. The cube of 6, is 216, a third part of it is 72; the pyramid KHOIF: this pyramid being taken from that prism, there rest 360; the prism RXOIFE, equal to all the squares in the portion RQE. Let from E to the third R be 9; its square 81, the half thereof 40½, the area RXE, this area being multiplied by 24, the product will be 972, the prism KHYREF: the cube of 9, is 729, a third part of it is 243, the pyramid KHOIF: this py­ramid being substracted from that prism, the re­mainder is 729; the prism RXOIFE, equal to all the squares in the third portion RQE. Having obtained these three portions, the rest may be found by their third difference, according to the X. Note.

[Page 15]

0 00 0 0      
99  
3 09 108 99 162
261 54
6 72 432 360 108
369 54
9 243 972 729 54
423 54
12 576 1728 1152 00
423 54
15 1125 2700 1575 54
369 54
18 1944 3888 1944 108
261 54
21 3087 5292 2205 162
99  
24 4608 6912 2304  
   
1 2 3 4 5 6 7

The numbers in the seventh colum are the third differences, and they equal; the numbers in the sixt colum are the second differences, and are com­posed by substracting the numbers in the seventh from the first and last numbers in the sixt colum; the numbers in the fifth colum are the first diffe­rences, and are composed by adding those num­bers in the sixt colum to the first and last of those in the fifth colum; the numbers in the fourth colum are all the squares in several portions of one fourth of a sphere whose diameter is 24, those por­tions are made by adding the numbers in the fifth colum to the numbers in the fourth, thus, 261, and 99, is 360. 369, and 360, is 729. 423, and 729, is 1152, &c.

Then making use of the first and second scho­lium the number of gallons are obta [...]ned. Or if it be made, as 14, is to 11, so is 54, to a fourth [Page 16] number, with that fourth number proceede to make tables of the second and first differences, and then the table of portions it selfe. Every sphere hath its third differences equall. To find the third difference, doe thus. Cube one of the equal segments of the axis and multiply that cube by 2, and that product will be the third difference, thus, the cube of three is 27, which multiplyed by 2, the product is 54; the third difference of all the squares in one fourth of a sphere. Here note, that it is to be understood, that the axis of the sphere is equally divided into an equal number of segments; so then, if the number of segments in the semiaxis, less by one; be multiplyed by the third difference, it gives the first of the second differences. Thus, the number of segments in the semiaxis is 4, then 4 less 1, is 3; which being multiplyed by 54, the product is 162: the first of the second differences.

To find the third difference in one fourth of all the squares in a spheroid, do thus: The axis being divided as above in the sphere; cube the difference betwixt two Segments, which being multiplyed by 2, makes a product; then, as the square of the semiaxis, is to the square of the other semidiameter; so is that former product to a fourth number, which will be the third diffe­rence. For the second differences, use the Rules given for the sphere.

XIV. Note.

To calculate a pyramid or cone gradually. To find the third difference in a pyramid work thus, [Page 17] the Altitude of the pyramid being equally divided▪ cube the difference of the two segments, which being doubled, makes a number; then, as the square of the Altitude of the pyramid, is to the area of the base of that pyramid; so is that for­mer number, to the third difference of that pyramid.

To find the second differences in a pyramid: As the difference of two of the segments of the Altitude, is to the following segment; so is the third difference, to the second difference answer­able to that segment.

To find the first differences in a pyramid. Cube two of the segments, and take a third part of their difference. Then, as the square of the Altitude of the pyramid; is to the area of the base of that pyramid; so is that former difference; to the first difference answerable to those two segments.

Let there be a pyramid whose Altitude is 10, and one side of the base is 40, and the other side 5; therefore the area of the base is 200. Let the Altitude be divided into five equall parts, and to calculate accordingly. To find the third differ­ence, the cube of 2, is 8; whose double is 16. Then, as 100 the square of the Altitude, is to 200 the area of the base; so is 16, to the third difference 32. To find any of the second differ­ences at demand, to find the second difference an­swerable to 8. As 2, the difference betwixt the segments 6, and 8, is to 8; so is the first difference 32, to 128 the second difference answerable to 8. The second differences are in proportion one to another, as their answering segments; as 2, is to [Page 18] 3▪2; so is 8, to 128. To find any of the first dif­ferences, cube the two Segments, to wit, 2 and 4, and the cubes will be 8 and 64; then take 8 from 64 and the Remainder is 56, a third part is 18⅔. then, as the square of the Altitude 100, is to the area of the base 200; so is 18⅔, to 37⅓, the first difference, answering to 2 and 4. Then by a continuall adding of the third difference to the second differences they are made, and by ad­ding the first of the second differences to the first of the first differences and so in order the first differences are made. Lastly by adding the first differences the Segments of the pyramid, are made according to the III. Note; or thus.

0 0      
5⅓  
2 5⅓ 32
37⅓ 32
4 42⅔ 64
101⅓ 32
6 144·· 96
197⅓ 32
8 341⅓ 128
325⅓  
10 666⅔  
   
1 2 3 4 5

The numbers in the fifth colum are the third differences, the first number in the fourth colum being found by the Rule before given, all the numbers in that fourth colum may be made by adding the third difference, thus, to 32 adde 32, the summe is 64. adde 32, to 64; the summe is 96. adde 32, to 96; the summe is 128. The first number in the third colum being found by the Rule above, then 5⅓ added to 32; the summe is 37⅓. [Page 19] adde 64, to 37⅓; the summe is 101⅓. adde 96, to 101⅓, the sum is 197⅓. adde 128, to 197⅓; the sum is 325⅓. further, adde the first of the third colum, to the first of the second colum; thus, adde 5⅓, to 0; the sum will be 5⅓, adde 57⅓, to 5⅓, the sum is 42⅔, adde 101⅓, to 42⅔; the sum is 144. adde 197⅓, to 144; the sum is 341⅓, adde 325⅓, to 341⅓; the sum is 666⅔.

If it be to calculate a cone whose diameters of the base are 40 and 5. Let it it be made, as 14, is to 11; so is 32, to the third difference of the same cone. Then proceede with the third dif­ference to make the second and first; and lastly, the table it self.

XV. Note.

The calculation of frustum pyramides whose bases are unlike, To the performance of which consider the third case of the second proposition of Stereom. Prop.

Every such solide hath its third differences equall, but the second and first differences will be complicated according to the IX. Note.

To find the third difference proper to the pyramid BCDHF, Let the construction and numbers be the same as in that diagram, and let it be to calculate it upon every two inches, thus. The cube of 2, is 8; the double thereof is 16, Then, as the square of the Altitude 40, that is 1600, is to the area of the base BCDH, 336; so is 16, to 336/100. by the Rule delivered in the [Page 20] 14 Note, the first of the second differences is 336/100. and the first of the first differences is 56/100.

The solide HDEGVF hath its second differ­ences equall by the VII. Note.

To find its first and second differences. The square of 2, is 4. which multiplyed by FV, 26; the product will be 104. then, as 40 the Altitude, is to HD, 28; so is 104, to 7280/100. the second difference. Therefore the first of the first differ­ences will be 3640/100.

To find the second differences of the solide ABHOIF the square of 2 is 4, which multi­plyed by IF, 30; the product is 120, then, as 40, the Altitude; is to OA, 12: so is 120, to 36, the second difference. Therefore the first of the first differences are 18. For the complication of these differences.

1 2 3  
[...]6/100 336/100 3 [...]6/100 in the pyramid BCDHF
3640/100 7280/100   in the prism HGEDFV
18 36   in the prism ABHOIF
5496/100 11216/100 336/100 their summe.

Rejecting the denominators they may be writ­ten Thus,

5496 11216 336

Because the denominators are Rejected, there­fore the two last figures toward the Right hand are decimals.

[Page 21]

0        
161496  
2 161496 11216
172712 336
4 334208 11552
184264 336
6 518472 11888
196152 336
8 714624 12224
208376 336
10 923000 12560
220936 336
12 1143936 12896
233832 336
14 1377768 13232
247064 336
16 1624832 13568
260632 336
18 1885464 13904
274536 336
20 2160000 14240
288776 336
22 2448776 14576
303352 336
24 2752128 14912
318264 336
26 3070392 15248
333512 336
28 3403904 15584
349096 336
30 3753000 15920
365016 336
32 4118016 16256
381272 336
34 4499288 16592
397864 336
36 4897152 16928
414792 336
38 5311944 17264
432056  
40 5744000  
   
1 2 3 4 5

[Page 22]The construction of the table may be thus; the numbers in the first colum are the third dif­ferences▪ The first number in the fourth colum is the complicated second difference, and the other number in that fourth colum are made thus, to the first 11216, adde 336; the sum is 11552. Then to that 11552, adde 336; the sum is 11888, &c.

The first number in the third colum is compli­cated from the first complicated difference and a parallelipepidon whose base is the plane RIFV, and the Altitude the first Segment of the Altitude of the frustum, thus, the plane RIFV, is 780; which being doubled is 1560; then, 156000 more 5496 is 161496; the first of the first differences, then 161496 more 11216, is 172712. Further, 172712 more 11552, is 184264. Yet further 184264 more 11888, is 196152, &c.

The numbers in the second colum are made thus, the first number in the second colum, is the same as the first number in the third colum, then, 161496 more 172712, is 334208, and 334208 more 184264, is 518472, &c.

Then makeing use of the first and second scho­lium, the quantity of Liquor that such vessels contain may easily be obtained.

XVI. Note.

To calculate Elliptick solides whose bases are unlike. The calculation of such solides are the same as in the 15, note for if the first, second and third complicated differences be found, then make­ing use of this propotion as 14, is to 11; so is 336; to the third difference.

[Page 23]And

As 14, is to 11; so is 11216, to the first of the second differences.

Further

As 14, is to 11; so is 161496, to the first of the first differences, then proceede to make the table it self, as in the 15 note. Or make use of the secund scholium of the 11 note and you will have the quantity in Gallons.

Or

Such Elliptick solides may be calculated by the 12 note: for every such Elliptick solide is equall to a frustum hyperbolick conoide whose circular bases of the conoide, are equall to the Elliptick bases of the Elliptick solide; and the Altitude of one frustum is equall to the Altitude of the other.

XVII. Note.

Every hyperbolick conoid hath its third diffe­rences equal.

To find the third, second and first differences in an hyperbolick conoid, and consequently to calculate that conoid gradually. In the foremen­tioned diagram of the 17. prop. Stereom. Prop. Let GM, the Transverse diameter be 12. ML, the parameter 6. MA, the axis of the conoid 24.

To calculate the solidity of this conoid vpon every three Inches.

To find the third difference of this conoid.

Take the difference of two of the Segments, to wit, 3; whose cube is 27: whose double is 54. Then, as GM, 12; is to ML, 6: so is 54, to 27. The third difference of all the squares in one fourth of that conoid proper to that pyramid FCDEL.

By the Rule in the last note the first of the second differences is 27.

For the first of the first differences, worke thus; take the first Segment which is 3; whose cube is 27; a third part is 9, then, as GM, 12; is to ML, 6: so is 9, to 4½. the first of the first differences proper to the pyramid FCDEL.

The second and first differences of all the squares in the fourth of this conoid, is complica­ted from the second and first differences of the pyramid FCDEL, and the second and first diffe­rences of the prism ABCFLM. Every such prism hath it second difference equall.

To find the second and first difference of the prism ABCFLM.

Square the difference of two of the Segments of the axis, to wit, 3▪ that is 9, which being multiplyed by the parameter ML, 6; the product is 54, the second difference. The first of the first d [...]fferences of every such prism is half of the [Page 25] second difference; therefore the first of the first differences is 27.

To complicate these differences.

1 2 3 differences
27 27 in the prism FCDEL.
27 54   in the prism ABCFLM.
31½ 81 27 in all the squares of one fourth of that hyperbolick conoid.

0 0      
31½  
3 31½ 81
112½ 27
6 144 108
220½ 27
9 364½ 135
355½ 27
12 720 162
517½ 27
15 1237½ 189
706½ 27
18 1944 216
922½ 27
21 2866½ 243
1165½  
24 4032  
   
1 2 3 4 5

In the first colum are the third differences. In the fourth colum the second differences. In the third colum the first differences. In the second colum the portions of all the squares of one fourth of an hyperbolick conoid, upon every three [Page 26] inches, whose Transverse diameter is 12, and parameter is 6, and axis is 24.

The construction of this table is the same as the former; thus, 81 more 27; is 108. more 27; is 135. more 27; is 162. &c.

31½. more 81; is 112½. more 108; is 220½. &c.

0 more 31½; is 31½. more 112½; is 144. more 220½. is 364½. more 355½; is 720.

Here remember that the Transverse diameter is found, by the 9 of the 23 Proposition. of Stereom. Prop. Also the parameter found by the converse of the first part of the 11 Prop. of Stereom. Prop. The parameter of the parabolike conoid is found, by the converse of the 9 Prop. Of Stereom. Prop.

XVIII. Note.

Cautions Concerning Reduction. 1

If it be to calculate pyramids whether Regular or Irregular, whole or frustums; the third, second and first differences are to be found as above: then Reduce those differences into Gallons and parts of a Gallon, or Barrells, or parts of a barrels;

Thus

Suppose 288 cubick inches make one Gallon, and 36 Gallons make one Barrell.

Then,

If the measure be taken in inches, divide the third, second and first differences by 288, and so there will be three quotients in Gallons or parts [Page 27] of a Gallon, then with those three quotients proceede to make the table of solid Segments, and that table will be in Gallons or parts of a Gallon. If it be to calculate a table in Barrells multiply 288 by 36 and the product will be 10368 the number of cubick inches in one Barrell. Then divide the third, second and first differences by 10368, there will be three quotients in Barrells or parts of a Barrell: Then with these three quotients proceede to make the table of solides Segments.

That table being so made will be in Barrells or parts of a Barrell.

2▪

To calculate Cones and Elliptick solids, whether the whole or their frustums.

Haveing found their third second and first differences, as above, and it be to calculate them in cubick inches, Let it be made as 14, is to 11; so is the third difference, to a fourth,

And,

As 14, is to 11; so is the second difference, to a fourth,

Further,

As 14, is to 11; so is the first difference, to a fourth with these three number thus found, proceede to make the table of solid Segments, and that table will be in cubick inches.

To calculate these solids in Gallons.

Multiply 14 by 288 the product will be 4032.

Then,

As 4032, to 11; so is the third difference, to a fourth.

[Page 28]And,

As 4032, to 11; so is the second difference, to a fourth.

Further,

As 4032, to 11; so is the first difference, to a fourth.

With these three numbers thus found, proceed to make the table of solid Segments. So that table will be in Gallons.

To calculate these solids in Barrells.

Suppose 288 cubick inches makes one Gallon, and 36 gallons makes one Barrell, then multiply 288, 36 and 14 one into another and they make 145152.

Then,

As 145152, is to 11; so is the third difference, to a fourth.

And,

As 145152, is to 11; so is the second difference, to a fourth.

Further,

As 145152, is to 11; so is the first difference, to a foruth.

With these three numbers thus found make the table of solid Segments: that table will be in Barrells.

III.

Having found the third, second and first diffe­rences of all the squares of one fourth of a sphere, spheroid and hyperbolick Conoid, as in the 12 and 13 notes and the second and first differences of all the squares of one fourth of a parabolick conoid as in the 11 note: they may be Reduced to Circular differences.

[Page 29]Thus▪

As 14, is to 11; so is the third difference, to a fourth.

And,

As 14, is to 11, so is the second difference, to a fourth.

Further,

As 14, is to 11; so is the first difference, to a fourth.

With these numbers thus found make a table, of solid Segments of cubical inches of one fourth of any of these solids.

These solid Segments ought to be multiplyed by four, to reduce them to solid Segments of a whole sphere, spheroid, hyperbolick and parabolick conoid: but to shun that work divide 14, by four, and then find the new differences; but because 14 cannot be just divided by four, therefore divide 14, by two, and multiply 11, by two, and then work; Thus,

Then,

As 7, to 22; so is that third difference, to a fourth.

And,

As 7 to 22; so is that second difference, to a fourth.

Further,

As 7, to 22; so is that first difference, to a fourth.

With these numbers thus found, proceed to make tables as is taught in those Notes: tables so made, will be tables of solid Segments of those solids, in cubick inches.

To calculate these solids in Gallons.

[Page 30]Multiply 288 by 14, whose product is 4032; one fourth thereof is 1008;

Then,

As 1008, is to 11; so is the third difference, to a fourth.

And

As 1008, is to 11; so is the second difference, to a fourth.

Further,

As 1008, is to 11; so is the first difference, to a fourth.

Tables being made, with numbers thus found; according to the former directions in the sphere, spheroid, hyperbolick and parabolick conoids, will be tables of solid Segments of a whole sphere, spheroid, hyperbolick and parabolick conoid, in Gallons or parts thereof.

To calculate these solids in Barrells.

Multiply 4032 by 36, the product will be 145152, one fourth thereof will be 36288;

Then,

As 36288, is to 11; so is the third difference, to a fourth.

And,

As 36288, is to 11; so is the second difference, to a fourth.

Further,

As 36288, is to 11; so is the first difference, to a fourth.

Tables being made, with numbers thus found, according to the former directions, will be tables of solid Segments in Barrells. &c.

[Page 31]Then,

Using a Rod or Ruler equally divided into inches as in scholium the first, the number of Gallons or Barrells may speedily be obtained.

As for the just magnitude of the Gallon, it i [...] not my businesse to dispute; that being deter­mined by custom or Authority: I took 288 onely for Example sake.

XIX. Note. In a Rank of numbers having equal differences.

Let the first term in the Rank be Z, its square ZZ. the second term 2Z, its square 4ZZ, there­fore the first of the first differences is 3ZZ, the third term in that Rank 3Z, its square 9ZZ, then 9ZZ, Less 4ZZ, the second of the first differences 5ZZ, therefore 5ZZ Less 3ZZ the second difference will be 2ZZ.

Further,

The fourth term in that Rank is 4Z, its square is 16ZZ, then 16ZZ Less 9ZZ the third of the first differences 7ZZ; again, 7ZZ Left 5ZZ the second difference is 2ZZ.

Hence it follows,

That the second difference is equall to the square of the first term doubled.

Or also,

The second difference is equall to the squar [...] [Page 32] of the difference of two of the terms, (in order taken) doubled.

By the same method we find that the third difference in a Rank of cubes are equall, and the third difference is equal to the first term multi­plyed by 6.

Or,

The third difference is equal to the cube of the difference of two of the terms, taken in order, multiplyed by 6.

The index and equal difference, of every power agrees; to wit, the index of the square is 2, and the second differences are equal. The index of the cube is 3, and the third differences are equal. The index of the square squared is 4, and the fourth differences are equal. &c.

The equal difference of every power, is com­plicated from the index of that power, and the equal difference of the next Lesser power.

Let the Rank be in naturall order, Thus; 1, 2, 3, 4. &c.

The indices of the powers, Thus.

1 2 3 4 5
Z ZZ ZZZ ZZZZ ZZZZZ

A unity the equal difference in that naturall Rank, whose square is 1, which multiplyed by 2 the index of the square the product is 2, the equal difference in the squares. 3, the index of the cube multiplyed by 2 the equal difference in the squares, [Page 33] the product is 6, the equal difference in the cubes▪ 4 the index of the square squared multiplyed by 6 the product is 24 the equall difference in the square squared, &c.

If the Rank be in order thus, 2, 4, 6, 8, &c.

2 the equal difference of this Rank whose square is 4; multiplyed by 2 the index of the square the product is 8; the equal difference of the squares in such a Rank. Because the equal diffe­rence of the Rank is 2, therefore the indices are to be doubled, &c.

And the equall difference of the powers in such a Rank will be 8, 48, 384, &c.

XX. Note. For the more easier calculation of the second sections of the sphere and spheroid; worke, Thus.

From the double of the superficies of the triangle BZN, substract the superficies of the triangles BZGD and NZPA, the Remainder will be the superficies of the triangles BZPA and NZGD, the areas of these two triangles being substracted from the area of the traingle NZB, the Remainder will be the superfice of the triangle ZGDAP.

FINIS.

By Iohn Baker, living in Barmonsey-street in South­wark, over against the Princes-Armes, is Taught Arithmetick, both in whole numbers and fractions, Decimal, Logarithmetical and Algebraical, Geome­try, Trigonometry, Astronomy, the use of Globes, Navigation, Measuring, Gageing, Dyalling, &c. Also the Construction and use of all the usual lines put upon Rules or Scales, He also teacheth how to find the (Length and) Spreading of a Hip­rafter, only by a Line of Chords of singular use for Carpenters, a way not as yet vulgarly known amongst Workmen.

Faults Escaped in the Impression of Stereometrical Propositions.

Page 1, line 18, for and Z Read and H. p. 10, l. 23, for 56, r. 58. p. 34, l. 25, after RI put. p. 43, for 297232, r. 297432. p. 45, for 18, r. V432▪ p. 46, l. 1. for XVI, r. XVII. and l. 21, for AE, 16; r. AF, 6; p. 48, l. 6, for 634. r. 624, p. 51. l. 22, for diameter, r. semidiameter. p. 58▪ l. 25, for ZB, r. XB▪ p. 63, l. 1, for XIII. r. XXIII. p. 100. l. 17, for parameter, r. diameter. p. 102 and 103 for as 4 to 3, r. as 3 to 2. p, 105. l. vlt. for Z+2▪ r. Z-2. p. 106, l. 4, for Z= [...] r. Z-⅗. and l. 25, for 89, r. 98.

p. 7 against 12 in the first col. in the sec. r. 576. and in the fifth colum f. 96 r. 99. p. 13. in the second col. f. 46. r. 36. and in the same col. f. 2216, r. 2916.

This keyboarded and encoded edition of the work described above is co-owned by the institutions providing financial support to the Text Creation Partnership. This Phase I text is available for reuse, according to the terms of Creative Commons 0 1.0 Universal. The text can be copied, modified, distributed and performed, even for commercial purposes, all without asking permission.